An introduction to the Weierstrass M-test: Part II
In this part, we continue from where we left off in Part I of this series on the Weierstrass M-test . First, let's recall our standing assumptions and notation. Throughout, I is a non-degenerate interval in \R, and (f_n)_{n=0}^\infty is a sequence of functions from I to \R. We denote the set \N \cup \{0\} of non-negative integers by \N_0. For each m \in \N_0 we define the function S_m: I\to \R by S_m = \sum_{n=0}^m f_n\,. So, for each x \in I, we have \Jdisplay S_m(x) = \sum_{n=0}^m f_n (x)\,. We also have a sequence (M_n)_{n=0}^\infty of non-negative real numbers such that \Jdisplay\sum_{n=0}^\infty M_n < \infty\,. For each m \in \N_0, we set R_m=\sum_{n=m+1}^\infty M_n\,. Recall that R_m \to 0 as m \to \infty, because the "tails of a convergent series" always tend to 0. Our first task is to prove the following theorem that we stated last time. Theorem 1 (Part of the ...