The Christmas Equation
I posted the following in December 2021 on my first-year pure module's Piazza forum.
Hi everyone
I saw this a few years ago on QI, and found another version on the web at
http://mathandmultimedia.com/2014/12/02/merry-christmas-equation/
If we are told that
\qquad\displaystyle y=\frac{\ln(\frac{x}m-sa)}{r^2}
multiplying by r^2 gives
\qquad yr^2=\ln(\frac{x}m-sa)\,.
Then taking e to the power of both sides give
\qquad\displaystyle e^{yr^2}=\frac{x}m-sa\,,
and multiplying both sides by m gives
\qquad me^{yr^2}=x-msa\,,
which can be rewritten as
\qquad me^{rry}=x-mas\,.
(And a Happy New Year!)
Best wishes,
Dr Feinstein
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